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Why does cos(90 - x) = sin(x) and sin(90 - x) = cos(x)?

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Note that the image below is only for x in Q1 (the first quadrant). If you wish you should be able to draw it with x in any quadrant. Definition of sin(x) (side opposite angle x)//(hypotenuse) Definition of cos(90^@ -x) (side adjacent to angle (90^@-x))//(hypotenuse) but (side opposite angle x) = (side adjacent to angle (90^@-x) Therefore sin(x) = cos(90^@ -x) Similarly cos(x) = sin(90^@ - x)

Give the coordinates of each image. $$ D _ { rac { 1 } {

Fill in the blank with the appropriate direction (left, righ

Give the coordinates of each image. $$ D _ { rac { 1 } {

Fill in the blank with the appropriate direction (left, righ

Solved SSC CHSL 2 July 2019 Shift-2 Paper With Solutions PDF, PDF, Interest

Solved SSC CHSL 2 July 2019 Shift-2 Paper With Solutions PDF, PDF, Interest

Why does cos(90 - x) = sin(x) and sin(90 - x) = cos(x)?

Trace triangle JKL and point P. Draw the dilation of triangl

Give the coordinates of each image. $$ D _ { rac { 1 } {

Fill in the blank with the appropriate direction (left, righ

Solved SSC CHSL 2 July 2019 Shift-2 Paper With Solutions PDF, PDF, Interest

Trace triangle JKL and point P. Draw the dilation of triangl

Solved SSC CHSL 2 July 2019 Shift-2 Paper With Solutions PDF, PDF, Interest