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∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in Figure). The height AD from A to BC, is 6 cm. Find the area of ∆ ABC. What will be the height from C to AB i.e., CE?
15. If ABC is an isosceles triangle with AB = AC = 7.5cm and BC
A triangle ABC has side of lengths a=14cm b=20cm c=7.5cm. What is
Triangle ABC is isosceles with AB = AC = 7.5cm and BC=9cm. The
In an isosceles triangle ABC with AB=AC and AD is perpendicular to BC
DeltaABC is isosceles with AB=AC=7.5cm and BC=9cm. The height AD
AABC is iso Fig 11.26 Cis isosceles with AB=AC = 7.5 cm and BC =9
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area
DeltaABC is isosceles with AB=AC=7.5cm and BC=9cm. The height AD from
∆ ABC is isosceles with AB AC = 7.5 cm and BC = 9 cm (Fig). The
Ex 9.1, 8 - ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm