At 300 K, 36 g of glucose present per litre in its solution has an osm

pi=CRT" (C = molar concentration)" (pi(1))/(pi(2))=(C(1))/(C(2))," "(4.98)/(1.52)=(36//180)/(C(2))" or "C(2)=(36)/(180)xx(1.52)/(4.98)="0.061 M"

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30 g of glucose present per litre has an osmotic pressure of 4.91 atm 303 K. If the osmotic pressure of the same solution is 1.5 atm the same tempera- ture, what

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If the elevation in boiling point of a solution of 10 g of solute (mol